M Karim Physics Numerical Book Solution Class 11 -

$$10 = \mu \times 5 \times 9.8$$

Given: $v = 20$ m/s, $u = 0$ m/s, $t = 5$ s m karim physics numerical book solution class 11

Using the equation: $$f = \mu N$$, where $\mu$ is the coefficient of friction and $N$ is the normal reaction. $$10 = \mu \times 5 \times 9

$$\mu = \frac{10}{5 \times 9.8} = 0.2$$

Given: $F = 20$ N, $m = 5$ kg, $a = 2$ m/s² $u = 0$ m/s